Question

Equivalent weight of $ {{K}_{2}}C{{r}_{2}}{{O}_{7}} $ in acidic medium is

• A. $ M $
• B. $ \frac{M}{2} $
• C. $ \frac{M}{5} $
• D. $ \frac{M}{6} $

Answer 1

Answer: (D)

Sol. $ {{K}_{2}}C{{r}_{2}}{{O}_{7}}+4{{H}_{2}}S{{O}_{4}}\xrightarrow{{}} $
$ {{K}_{2}}S{{O}_{4}}+C{{r}_{2}}{{(S{{O}_{4}})}_{3}}+4{{H}_{2}}O+3[O] $
or $ C{{r}_{2}}O_{7}^{2-}+14{{H}^{+}}+6{{e}^{-}}\xrightarrow{{}}2C{{r}^{3+}}+7{{H}_{2}}O $
Equivalent weight of $ {{K}_{2}}C{{r}_{2}}{{O}_{7}}=\frac{molecular\text{ }mass}{6} $