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Chemistry
Equivalent weight of H3PO2 in a reaction is found to be half of its molecular weight. It can be due to its
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Q. Equivalent weight of $H_{3}PO_{2}$ in a reaction is found to be half of its molecular weight. It can be due to its
Redox Reactions
A
oxidation to $H_{3}PO_{3}$
B
reaction of two $H^{+}$ ions
C
oxidation to $H_{3}PO_{4}$
D
reduction to $PH_{3}$
Solution:
(a) It is monobasic acid, hence only one $H^{+}$can be neutralised $E=\frac{M}{1}$