Q.
Equivalent resistance of the given infinite circuit is
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Solution:
$\frac{R\times2}{R+2}+4=R$
$2R +4R+8=R^{2}+2R$
$R^{2}-4R-8=0$
$R=\frac{4\pm\sqrt{16+32}}{2}$
$=\frac{4+\sqrt{48}}{2} =5.46\Omega$