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Q. Equivalent mass of potassium permanganate in acid medium is

COMEDKCOMEDK 2006The d-and f-Block Elements

Solution:

In acidic medium,
$M^{+7} nO^-_4 + 8H^+ + 5e^- \rightarrow Mn^{2+} + 4H_2O$
Total number of electrons gained $= 5$
Total change in the oxidation number of $Mn = 7 - 2 = 5$
Eq. mass of $KMnO_4 = \frac{ Mol.mass \, of\, KMnO_4}{5} $