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  4. Equivalent mass of K2Cr2O7 in acidic solution is equal to

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Q. Equivalent mass of $K_2Cr_2O_7$ in acidic solution is equal to

COMEDKCOMEDK 2010The d-and f-Block Elements

Solution:

$\overset{\text{+6}}{C}r_2 O^{2-}_7 + 14 H^+ + 6e^- \rightarrow 2Cr^{3+} + 7H_2O $
Total number of electrons gained = 6
Total change in oxidation number of Cr
=$2(+6) - 2(+3) = 6 $
Eq.mass of $K_2Cr_2O_7 = \frac{Mol.mass \, of \, K_2 Cr_2 O_7}{6} $