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Q. Equivalent mass of a metal is double that of oxygen. How many times is the equivalent mass of its oxide greater than that of the metal?

Some Basic Concepts of Chemistry

Solution:

$M + O _{2} \longrightarrow M _{ x } O _{ y }$

Equivalent mass of oxygen $=8$

Equivalent mass of metal $=16$

Equivalent mass of metal oxide $=24$

Thus, $\frac{E(\text { metal oxide })}{E(\text { metal })}=\frac{24}{16}=1.5$