1. Tardigrade
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  3. Chemistry
  4. Equivalent amounts of H2 and I2 are heated in a closed vessel till equilibrium is obtained. If 80% of the hydrogen can be converted to HI, the Kc at this temperature is

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Q. Equivalent amounts of $H_2$ and $I_2$ are heated in a closed vessel till equilibrium is obtained. If 80% of the hydrogen can be converted to $HI$, the $K_c$ at this temperature is

VITEEEVITEEE 2007

Solution:

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$ K_{c}=\frac{[ HI ]^{2}}{\left[ H _{2}\right]\left[ I _{2}\right]} $
$=\frac{1.6 \times 1.6}{0.2 \times 0.2} $
$ K_{c} =64$