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Q.
Equipotential surfaces
Electrostatic Potential and Capacitance
Solution:
Electric field, $E=-\frac{dV}{dr}$ or $dr \propto\frac{1}{E}$
i.e., equipotential surfaces are closer in regions of large electric fields compared to regions of lower electric field. At sharp edges of a conductor, charge density is more. Therefore electric field is stronger. Hence equipotential surfaces are more crowded