Question

Equilibrium constant for two complexes are
$A:$ $K_{4}\left[\right.Fe\left(\right.CN\left(\left.\right)_{6}\left]\right.$ $2.6\times 10^{37}$ (for dissociation)
$B:K_{3}\left[\right.Fe\left(\right.CN\left(\left.\right)_{6}\left]\right.$ $1.9\times 10^{17}$ (for dissociation)

• A. A and B are equally stable
• B. A is more stable than B
• C. B is more stable than A
• D. the predictable stability

Answer 1

Answer: (C)

Here $K_{3}\left[\right.Fe\left(\right.CN\left(\left.\right)_{6}\left]\right.$ with dissociation constant $1.9\times 10^{17}$ is more stable than $K_{4}\left[\right.Fe\left(\right.CN\left(\left.\right)_{6}\left]\right.$ with dissociation constant $2.6\times 10^{37}$
Higher is the dissociation constant lesser will be the stability of complex.