1. Tardigrade
  2. Question
  3. Chemistry
  4. Equilibrium constant for the given reaction is K =1020 at temperature 300 K A ( s )+2 B text (aq.) leftharpoons 2 C text (s) + D text (aq.) K =1020 Calculate the equilibrium conc. of B starting with mixture of 1 mole of A and 1 / 4 mole/litre of B at 300 K (Give your answer by multiplying it by 1011 )

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Q. Equilibrium constant for the given reaction is $K =10^{20}$ at temperature $300\, K$
$A ( s )+2 B \text { (aq.) } \rightleftharpoons 2 C \text { (s) }+ D \text { (aq.) } K =10^{20}$
Calculate the equilibrium conc. of $B$ starting with mixture of $1$ mole of $A$ and $1 / 4$ mole/litre of $B$ at $300\, K$ (Give your answer by multiplying it by $10^{11}$ )

Equilibrium

Solution:

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$10^{20}=\frac{\frac{1}{4}}{[ B ]^{2}} \Rightarrow 10^{20}=\frac{\frac{1}{4}}{a^{2}}$
$\Rightarrow a^{2}=\frac{1}{4 \times 10^{20}}=\frac{10^{-20}}{4} $
$\Rightarrow a=\frac{10^{-10}}{2}=5 \times 10^{-11} M$