1. Tardigrade
  2. Question
  3. Chemistry
  4. Equilibrium constant for the following equilibrium is given at 0oC. Na2HPO4 .12H2O(s) leftharpoons Na2HPO4 . 7H2O(s) + 5H2O(g) Kp = 31.25 × 10-13 At equilibrium what will be partial pressure of water vapour:

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Q. Equilibrium constant for the following equilibrium is given at $0^{o}C$.
$Na_{2}HPO_{4} .12H_{2}O(s) \rightleftharpoons Na_{2}HPO_{4} . 7H_{2}O(s) + 5H_{2}O(g)$
$K_{p} = 31.25 \times 10^{-13}$
At equilibrium what will be partial pressure of water vapour:

Equilibrium

Solution:

$Na_{2}HPO_{4} .12H_{2}O(s) \rightleftharpoons Na_{2}HPO_{4} 7H_{2}O_{4} (s) + 5H_{2}O (g)$
$K_{p} = 31.25 \times 10^{-13}$
$K_{P} = (P_{H_{2}O})^{5}$
$(P_{H_{2}O})^{5} = 31.25 \times 10-13$
$(P_{H_{2}O}) = (3125)^{1/5} \times (10^{-15})^{1/5}$
$(P_{H_{2}O}) = 5 \times 10^{-3}$