Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
Equation of a tangent to the hyperbola 5x2 - y2 = 5 and which passes through an external point (2, 8) is
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. Equation of a tangent to the hyperbola $5x^2 - y^2 = 5$ and which passes through an external point (2, 8) is
WBJEE
WBJEE 2019
A
3x - y + 2 = 0
B
3x + y - 14 = 0
C
23x - 3y - 22 = 0
D
3x - 23y + 178 = 0
Solution:
Let the tangent be $\quad y = mx \pm \sqrt{m^{2}-5}$
Since it passes through (2, 8) $\quad\Rightarrow \,\left(8-2m\right)^{2} = m^{2}-5$
$\Rightarrow 3m^{2} - 32m + 69 = 0\quad \Rightarrow 3m^{2} - 9m - 23m + 69 = 0 \quad\Rightarrow \left(3m - 23\right) \left(m - 3\right) = 0\quad \Rightarrow m = 3$ or $\frac{23}{3}$