Q. Equation of a tangent to the curve $y \cot x=y^3 \tan x$ at the point where the abscissa is $\frac{\pi}{4}$ is :
Application of Derivatives
Solution:
$ y \cot ^2 x-y^3=0 \Rightarrow y\left(y^2-\cot ^2 x\right)=0$
hence the curve is $y=0$ or $y^2=\cot ^2 x$
