Thank you for reporting, we will resolve it shortly
Q.
Equation of a line passing through $(1, 2, -3)$ and parallel to the line $\frac{x-2}{1}=\frac{y+1}{3}=\frac{z-1}{4}$ is
Three Dimensional Geometry
Solution:
Since, the line is parallel to the line
$\frac{x-2}{1}=\frac{y+1}{3}=\frac{z-1}{4}$
$\therefore D$.$r$.$'s$ of the required line are $< 1$, $3$, $4>$
Hence, equation of the line passing through $\left(1,2, -3\right)$ with $d$.$r$.$'s\, < 1$, $3$ , $4 >$ is
$\frac{x-1}{1}=\frac{y-2}{3}=\frac{z+3}{4}$