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  4. Equal volumes of two solutions, one having pH 6 and the other having pH 4 are mixed. The pH of the resulting solution would be

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Q. Equal volumes of two solutions, one having $pH\, 6$ and the other having $pH \,4$ are mixed. The $pH$ of the resulting solution would be

Equilibrium

Solution:

$\left[ H _{3} O ^{+}\right] =\frac{10^{-6}+10^{-4}}{2}=5.05 \times 10^{-5} $

$ pH =-\log \left(5.05 \times 10^{-5}\right)=4.3 $