Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Equal masses of $SO_{2} CH_{4}$ and $O_{2}$ are mixed in an empty container at $298\, K$, when total pressure is 2.1 atm. The partial pressure of $CH_{4}$ in the mixture is

States of Matter

Solution:

Let $w\, g$ of each $SO_{2} CH_{4}$ and $O_{2}$ are mixed.
$\therefore $ Mole fraction,
$X_{CH_4} = \frac{n_{CH_4}}{n_{SO_2} +n_{CH_4} +n_{O_2}}$
$- \frac{\frac{w}{16}}{\frac{w}{64} +\frac{w}{16} +\frac{w}{32}} = \frac{4}{7}$
(Molecular weight of $SO_{2} = 64 u, CH_{4} = 16 u, O_{2} = 32 u$) Partial pressure of $CH_{4}$
$P_{CH_4}$ = Mole fraction $\times$ Total pressure$\frac{4}{7} \times 2.1 = 1.2\, atm$