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Q. Enthalpy of sublimation of iodine is $24 \; cal \; g^{-1}$ at $200^{\circ}C$. If specific heat of $I_2(s)$ and $I_2(vap)$ are $0.055$ and $0.031\, cal\, g^{-1}K^{-1}$ respectively, then enthalpy of sublimation of iodine at $250^{\circ}C$ in $cal\, g^{-1}$ is :

JEE MainJEE Main 2019Thermodynamics

Solution:

$I_{2(s)} \rightarrow I_{2(g)} : \Delta H_1 = 24 \; cal/g \; at \; 200^{\circ} C$
$ \Delta H_2 = \Delta H_1 + \Delta C_{P_{rxn}} (T_2-T_1)$
= $24 + (0.031 -0.055) \times 50$
= $24-1.2$
= $22.8\, Cal/g$