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Chemistry
Energy required to dissociate 4 g of gaseous hydrogen into free gaseous atoms is 208 kcal at 25°C. The bond energy of H - H bond will be
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Q. Energy required to dissociate $4\, g$ of gaseous hydrogen into free gaseous atoms is $208\, kcal$ at $25^{\circ}C$. The bond energy of $H - H$ bond will be
Thermodynamics
A
$104\, kcal$
100%
B
$10.4\, kcal$
0%
C
$1040\, kcal$
0%
D
$1.04\, kcal$
0%
Solution:
Bond energy$=\frac{208}{4}\times2=104\, kcal$