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Q. Energy required to accelerate a car from 10 m/s to 20 m/s compared with that required to accelerate it from 0 to 10 m/s is

CMC MedicalCMC Medical 2008

Solution:

$ {{E}_{1}}=\frac{1}{2}m\,(v_{2}^{2}-v_{1}^{2}) $ $ \therefore $ $ {{E}_{1}}=\frac{1}{2}m\,[{{(20)}^{2}}-{{(10)}^{2}}] $ $ \Rightarrow $ $ {{E}_{1}}=\frac{1}{2}m\,(400-100) $ $ \Rightarrow $ $ {{E}_{1}}=\frac{1}{2}m\,\times 300=150\,m $ ?(i) $ {{E}_{2}}=\frac{1}{2}m\,[{{(10)}^{2}}-0] $ $ \Rightarrow $ $ {{E}_{2}}=\frac{1}{2}m\,\times 100=50\,m $ ?(ii) From Eqs. (i) and (ii), we have $ {{E}_{1}}=3{{E}_{2}} $