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Q. Energy required for the electron excitation in $Li ^{++}$ from the first to the third Bohr orbit is

AIEEEAIEEE 2011Atoms

Solution:

$ E =-13.6(3)^{2}\left[\frac{1}{3^{2}}-\frac{1}{1^{2}}\right] $
$=13.6 \times 9 \times \frac{8}{9} $
$=108.8 eV $