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Q. Energy per unit volume represents

NTA AbhyasNTA Abhyas 2022

Solution:

$\frac{\left[\right. E n e r g y \left]\right.}{\left[\right. V o l u m e \left]\right.}=\frac{\left[\right. M L^{2} T^{- 2} \left]\right.}{\left[\right. L^{3} \left]\right.}=\left[\right.ML^{- 1}T^{- 2}\left]\right.$
[pressure]= $\frac{\left[\right. M L T^{- 2} \left]\right.}{\left[\right. L^{2} \left]\right.}=\left[\right.ML^{- 1}T^{- 2}\left]\right.$