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Chemistry
Energy of one mole of photons of radiation whose frequency is 5× 1014 Hz is
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Q. Energy of one mole of photons of radiation whose frequency is $ 5\times 10^{14}\,Hz $ is
J & K CET
J & K CET 2014
Structure of Atom
A
$ 199.51\,kJ\,mol^{-1} $
65%
B
$ 189.51\,kJ\,mol^{-1} $
5%
C
$ 198.51\,kJ\,mol^{-1} $
26%
D
$ 188.51\,kJ\,mol^{-1} $
3%
Solution:
$\because$ Energy of $1$ photon, $R=h v$
$\therefore $ Energy of $1$ mole of photon,
$E'=N_{A} h v$
$=6.022 \times 10^{23} \times 6.626 \times 10^{-34} \times 5 \times 10^{14}$
$=199.508 \times 10^{3} J\,mol ^{-1}$