Q. Energy of activation of forward reaction for an endothermic process is $50\, kJ$. If enthalpy change for forward reaction is $20 \,kJ$ then enthalpy change for backward reaction will be
Solution:
For endothermic reaction,
$E_{a,\,b} = E_{a,\,f } -\Delta H^{\circ}$
$= 50\, kJ\, - 20\, kJ\, = 30\, kJ$
