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Q.
Energy needed in breaking a drop of radius $R$ into $n$ identical drops of radii $r$ is given by
NTA AbhyasNTA Abhyas 2020
Solution:
Energy needed = Increment in surface energy = (surface energy of n small drops) - (surface energy of one big drop) $= n 4 \pi r^{2} T - 4 \pi R^{2} T = 4 \pi T \left(\right. n r^{2} - R^{2} \left.\right)$