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Q. Energy equivalent to $ 10.00\text{ }c{{m}^{-1}} $ is

ManipalManipal 2013

Solution:

$ v=\frac{1}{\lambda } $ $ 10c{{m}^{-1}}=\frac{1}{\lambda } $ or $ \lambda =\frac{1}{10}cm=0.1\,cm=0.001m $ $ E=\frac{hc}{\lambda }=\frac{6.626\times {{10}^{-34}}\times 3\times {{10}^{8}}}{0.001}=19.878\times {{10}^{-23}} $ $ \approx 2.0\times {{10}^{-22}}J/atom=12.04\times 10\text{ }J/mol $ $ =12.04\times {{10}^{-2}}kJ\text{ }mo{{l}^{-1}}=28.6\times {{10}^{-3}}kcal\text{ }mo{{l}^{-1}} $