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Q. Energy E is stored in a parallel plate capacitor $ {{C}_{1}}. $ An identical uncharged capacitor $ {{C}_{3}} $ is connected to it, kept in contact with it for a while and then disconnected the energy stored in $ {{C}_{2}} $ is:

EAMCETEAMCET 2005Electrostatic Potential and Capacitance

Solution:

Let capacitance of a parallel plate capacitor $ {{C}_{1}}=C $ If energy stored in capacitor $ {{C}_{1}} $ is E. The charge on capacitor $ q=\sqrt{2EC} $ $ \left( \because E=\frac{1}{2}\frac{{{q}^{2}}}{C} \right) $ When. another uncharged capacitor $ {{C}_{2}} $ having same capacitance C is connected to it then total charge on both capacitor = q When disconnected, the charge on each one capacitor $ q=\frac{q}{2}=\frac{\sqrt{2EC}}{2}=\sqrt{\frac{EC}{2}} $ $ \therefore $ Energy stored in $ {{C}_{2}} $ $ E=\frac{1}{2}\frac{q{{}^{2}}}{C} $ $ =\frac{1}{2}\frac{EC}{2}\frac{1}{C} $ $ E=\frac{E}{4} $