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Q. End product of the following reaction is $ \ce{CH3CH2COOH ->[\text{Cl}_2][\text{red P}]X ->[\text{Alc KOH}]} $

MHT CETMHT CET 2008

Solution:

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$\ce{->[{\text{Alcoholic} KOH}][{\text{(elimination)}}]}CH_{2} = \underset{\text{acrylic acide}}{CHCOOH}$