Question

End product of the following reaction is :
$CH_3CH_2COOH \ce{->[Cl_2][red P]}$
$\ce{->[\text{alcoholic}KOH]}$

• A. $CH_3\underset{\overset{|}{O}H}{CH}COOH$
• B. $\underset{\overset{|}{O}H}{CH_2}CH_2COOH$
• C. $CH_2 = CHCOOH$
• D. $\underset{\overset{|}{C}l}{CH_2}\underset{\overset{|}{O}H}{CH}COOH$

Answer 1

Answer: (C)

$CH_3CH_2COOH \ce{->[Cl_2][\text{red}\, p
(HVZ \text{reaction})]} CH_3\underset{\overset{|}{C}l}{C}HCOOH$

$\ce{->[\text{alcoholic} KOH][\text{(elimination)}]}\underset{\text{Acrylic acid}}{CH_2 = CHCOOH}$