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Q.
Emission of a beta particle by an atom of an element results in the formation of:
ManipalManipal 2003Structure of Atom
Solution:
${ }_{1} H ^{3} \longrightarrow { }_{2} He ^{3}+{ }_{-1} e^{0}$
${ }_{1} H ^{3}$ and ${ }_{2} He ^{3}$ are isobars (having same mass no.)
As, in the emission of $\beta$-particle, mass number does not change. Hence isobars are obtained.