Question

EMF of the following cell is $0.6$ volt.

$Ag\left(s\right)\left|A g B r \left(s\right)\right|KBr\left(0.01 M\right)\left|\right.\left|\right.AgNO_{3}\left(0.001 \, M\right)\left|\right.Ag\left(\right.s\left.\right)$

$K_{s p}$ of $AgBr$ is expressed as $1\times 10^{- x}, \, x$ is

$\left[T a k e \frac{2.303 R T}{F} = 0.06 V\right]$

Answer 1

$Ag \rightarrow Ag^{+}\left(L\right)+ \, e^{-}$

$Ag^{+}\left(0.001 \, M\right)+e^{-} \rightarrow Ag$

$Ag^{+}\left(\right.0.001 \, M\left.\right) \rightarrow Ag^{+}\left(\right.L\left.\right)$

$0.6=0-\frac{0.06}{1}log\frac{K_{s p}}{10^{- 2} \times 10^{- 3}}$

$10^{- 10}=\frac{K_{s p}}{10^{- 5}}\Rightarrow K_{s p}=10^{- 15}$