Question

Emf of generator is $6 \,V$ and internal resistance is $0.5\, k \Omega$. If internal resistance of voltmeter is $2.5\, k \Omega$. then reading of voltmeter must be

• A. 10-3 V
• B. 1 V
• C. 5 V
• D. 10 V

Answer 1

Answer: (C)

Current flowing through the circuit $I=\frac{V}{R+G}$
$=\frac{6}{(2.5+0.5) \times 1000}=\frac{1}{500} A$
$\therefore $ Reading of voltmeter,
$V=I \times G=\frac{1}{500} \times 2.5 \times 1000=5$ volt