Q.
EMF diagram for iron is given as:
$\underset{(Fe = +6)}{E ^{\circ}\text{(volts)}FeO _{4}^{2-}} \xrightarrow{+2.20} \underset{(Fe = +3)}{Fe ^{3+}} \xrightarrow{+0.77} \underset{(Fe = +2)}{Fe ^{2+}} \xrightarrow{-0.445} \underset{(Fe = +0)}{Fe ^{0}}$
Determine the value of $E _{ FeO _{4}^{2-} / Fe ^{2+}}^{\circ}$
Electrochemistry
Solution: