Question

Electronic configuration of an element 'X' having atomic number 24 is

• A. [ A r ] $ 3d^5 \, 4s^1$
• B. [ Ar ] $ 3d^4 \, 4s^2$
• C. [ Ne ] $ 2p^5 \, 3s^1$
• D. [ Ar ] $ 3d^6 \, 4s^2$

Answer 1

Answer: (A)

The electronic configuration of element (X) (at. no.= 24) is
= $ 1s^2, \, 2s^2, \, 2p^6, \, 3s^2, \, 3p^6, \, 4s^1, \, 3d^5 $
(One electron jumps from 4s- orbital to 3d orbital to gain more stability.)
X = [ A r ] $ 3d^5 \, 4s^1$