1. Tardigrade
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  3. Chemistry
  4. Electromagnetic radiation of wavelength 663 nm is just sufficient to ionise the atom of metal A. The ionization energy of metal A in kJ mol-1 is .(Rounded-off to the nearest integer) [ h =6.63 × 10-34 Js , c =3.00 × 108 ms -1. . N A =6.02 × 1023 mol -1]

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Q. Electromagnetic radiation of wavelength 663 $nm$ is just sufficient to ionise the atom of metal A. The ionization energy of metal A in kJ $mol^{-1}$ is _____.(Rounded-off to the nearest integer)
$\left[ h =6.63 \times 10^{-34} Js , c =3.00 \times 10^{8} ms ^{-1}\right.$
$\left. N _{ A }=6.02 \times 10^{23} mol ^{-1}\right]$

JEE MainJEE Main 2021Structure of Atom

Solution:

$ E =\frac{h c}{\lambda} \times \frac{N_{A}}{1000}$

$=\frac{6.63 \times 10^{-34} \times 3 \times 10^{8} \times 6.02 \times 10^{23}}{663 \times 10^{-9} \times 1000} $

$=3 \times 6.02 \times 10 kJ $

$=180.6 kJ $