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Q. Electromagnetic radiation falls on a metallic body whose work function is $2\, eV$. For a particular radiation of frequency $v$, the maximum kinetic energy of the photoelectron is found to be $4 \, eV$. What would be the maximum kinetic energy of photoelectron for the radiation of frequency $\frac{5 v}{3}$ ?

Dual Nature of Radiation and Matter

Solution:

$h v=\phi+K_{\max }$ $h v=2+4=6 \,eV$
Now, $h\left(\frac{5}{3} v\right)=2+K_{\max }$
$K_{\max }=\frac{5}{3} \times 6-2 \Rightarrow K_{\max }=8 \,eV$