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Q. Electrolysis of a solution of $MnSO_{4}$ in aqueous sulphuric acid is a method for the preparation of $MnO_{2}$. Passing a current of $27\, A$ for $24$ hours gives $1\, kg$ of $MnO_{2}$ The current efficiency in this process is:

Electrochemistry

Solution:

$\frac{1000\times2}{\left(55+32\right)}=\frac{27\times24\times3600\times\eta}{96500}or \eta=0.921=95.1\%$