Question

Electrode potential data are given below $ F{{e}^{3+}}(aq)++{{e}^{-}}F{{e}^{2+}}(aq) $ $ E{}^\circ =+0.77V $ $ A{{l}^{3+}}(aq)+3{{e}^{-}}\xrightarrow[{}]{{}}Al(s) $ $ E{}^\circ =-1.66\,V $ $ B{{r}_{2}}(aq)+2{{e}^{-}}\xrightarrow[{}]{{}}2B{{r}^{-}}(aq) $ $ E{}^\circ =+1.08\,V $ Based on the data given above, reducing power of $ F{{e}^{2+}},Al $ and $ B{{r}^{-}}, $ will increase, in the order

• A. $ B{{r}^{-}}
• B. $ F{{e}^{2+}}
• C. $ Al
• D. $ Al

Answer 1

Answer: (A)

Reducing power ie, the tendency to lose electrons increases as the reduction potential decreases so the increasing order of reducing power of the given ions is $ B{{r}^{-}}~