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Q. Electrochemical equivalent of $Cu$ in the reaction $Cu ^{2+}+2 e ^{-} \longrightarrow Cu$ is

Electrochemistry

Solution:

$W =\frac{ E }{96500} \times it$
$\therefore Z=\frac{ E }{96500}=\frac{\frac{ M }{ n -\text { factor }}}{96500}$
$ \Rightarrow \frac{63.5}{2 \times 96500}$
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