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  4. Electric flux emanating through a surface element ds=5 hati placed in an electric field vecE=4 hati+4 hatj+4 hatk is

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Q. Electric flux emanating through a surface element $ \overrightarrow{ds}=5\hat{i} $ placed in an electric field $ \vec{E}=4\hat{i}+4\hat{j}+4\hat{k} $ is

J & K CETJ & K CET 2009Electric Charges and Fields

Solution:

Electric flux
$\phi=\vec{E} \cdot \overrightarrow{d s}$
$\therefore \phi=(4 \hat{i}+4 \hat{j}+4 \hat{k})(5 \hat{i})$
$=20$ units