Question

Electric field is maximum due to a charged ring of radius $R$ at a distance from circumference of the ring :

• A. $\frac{ R }{\sqrt{2}}$
• B. $\sqrt{\frac{3}{2}} R$
• C. $\frac{\sqrt{3}}{2} R$
• D. $\sqrt{2} R$

Answer 1

Answer: (B)

$x=\sqrt{R^{2}+\frac{R^{2}}{2}}=\sqrt{\frac{3}{2}} R$