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Q. Electric field inside the given capacitor with dielectric is $E$ and dielectric constant of material is $K$. Find charge density $\sigma$ on the plates. (Given $E \,=\, 6 \times 10^5 V/m, K \,= \,6$)Physics Question Image

AIIMSAIIMS 2018Electrostatic Potential and Capacitance

Solution:

$E=\frac{\sigma}{\varepsilon_{0}.K}; 6\times10^{5}=\frac{\sigma}{8.85\times10^{-12}\times6}$
$\sigma=36 × 8.85 × 10^{-12}\times10^{5} C/m^{2}$
$\sigma=3.18 × 10^{-5} C/m^{2}$