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  4. Electric field due to infinite, straight uniformly charged wire varies with distance 'r' as

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Q. Electric field due to infinite, straight uniformly charged wire varies with distance '$r$' as

KCETKCET 2021Electric Charges and Fields

Solution:

$\vec{ E }=\frac{1}{4 \pi \varepsilon_{0}} \frac{2 \lambda}{ r }$
(or) $\vec{ E }=\frac{\lambda}{2 \pi \varepsilon_{0} r } \hat{ r } $
$\Rightarrow |\vec{ E }| \propto \frac{1}{ r }$