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Q. Electric displacement is given by $D=\epsilon E$ , here, $\epsilon =$ electric permittivity, $E=$ electric field strength
The dimensions of electric displacement are

NTA AbhyasNTA Abhyas 2022

Solution:

Electric displacement, $D=\epsilon E$
Unit of $D=\frac{C^{2}}{N m^{2}}\frac{N}{C}$
$\therefore \, \left[D\right]=\left(\frac{C}{m^{2}}\right)=\frac{\left[\right. A T \left]\right.}{\left[\right. L^{2} \left]\right.}=\left[\right.L^{- 2}TA\left]\right.$