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  4. Eight drops of mercury of equal radii possessing equal charges combine to form a big drop. Then the capacitance of bigger drop compared to each individual small drop is

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Q. Eight drops of mercury of equal radii possessing equal charges combine to form a big drop. Then the capacitance of bigger drop compared to each individual small drop is

Electrostatic Potential and Capacitance

Solution:

Volume of 8 small drops $=$ Volume of big drop
$8 \times \frac{4}{3} \pi r^{3}=\frac{4}{3} \pi R^{3}$
$\Rightarrow R=2 r$
As capacity is proportional to $r$, hence capacity becomes 2 times.