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  4. Edge length of face centred cubic unit cell of an ionic solid AB is 508 pm. If the radius of A+ ion is 110 pm, the radius of B- ion in pm will be

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Q. Edge length of face centred cubic unit cell of an ionic solid AB is 508 pm. If the radius of $A^{+}$ ion is 110 pm, the radius of $B^{-}$ ion in pm will be

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Solution:

Edge length $=2r_{A^{+}}+2r_{B^{-}}$

$508=2\times 110+2r_{B^{-}}$

$2r_{B^{-}}=508-220=288$

$r_{B^{-}}=144$ pm