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Q. Each of two large conducting parallel plates has one sided surface area $A$. If one of the plates is given a charge $Q$ whereas the other is neutral, then the electric field at a point in between the plates is given by

Electric Charges and Fields

Solution:

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$ E_{\text {net }} =\frac{Q}{4 A \varepsilon_{0}} \times 2 $
$=\frac{Q}{4 A \varepsilon_{0}} $