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Q.
Each capacitor shown in the figure is $2 \, \mu F. \, $ Then the equivalent capacitance between points $A$ and $B$ is
NTA AbhyasNTA Abhyas 2022
Solution:
The figure is a balanced Wheatstone bridge, so diagonal capacitor will be ineffective.
So, the equivalent circuit will be as shown in the figure.
Equivalent capacitance of upper arms in series
$ \, \, C_{1}=\frac{2 \times 2}{2 + 2}=1\mu F$
Similarly, for lower arm
$ \, \, \, C_{2}=1\mu F$
$\therefore \, \, C_{A B}=C_{1}+C_{2}$
$ \, \, =1+1=2\mu F$
