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  3. Chemistry
  4. E n =-313.6 / n 2 kcal / mole. If the value of E =-34.84 kcal / mole, to which value does ' n ' correspond?

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Q. $E _{ n }=-313.6 / n ^{2} kcal / mole$. If the value of $E =-34.84\, kcal / mole$, to which value does ' $n$ ' correspond?

Structure of Atom

Solution:

$E _{ n }=\frac{-313.6}{ n ^{2}}$
$E=-34.84$
$\therefore -34.84=\frac{-313.6}{n^{2}}$
$n^{2}=\frac{-313.6}{-34.84}=9$
$n=\sqrt{9}=3$
$n=3$