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Q. $E,m,p$ and $G$ denotes energy, mass, angular momentum and gravitational constant. Then which option can be equivalent to $\frac{E p^{2}}{m^{5} G^{2}}$ in dimensions.

NTA AbhyasNTA Abhyas 2020

Solution:

$E=ML^{2}T^{- 2};m=M;p=ML^{2}T^{- 1}$
$G=M^{- 1}L^{3}T^{- 2}$
$\therefore \frac{E p^{2}}{m^{5} G^{2}}=\frac{M L^{2} T^{- 2} \cdot M^{2} L^{4} T^{- 2}}{M^{5} \cdot M^{- 2} L^{6} T^{- 4}}=$ no dimension
$\therefore $ it represent angle which has no dimension.