Tardigrade
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Chemistry
During titration, H2SO4 is preferably used over HCl and HNO3 to make the solution acidic because
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Q. During titration, $H_2SO_4$ is preferably used over HCl and $HNO_3$ to make the solution acidic because
The d-and f-Block Elements
A
$H_2SO_4$ is a strong oxidizing agent and it reacts with $KMnO_4$ during titration
11%
B
some $KMnO_4$ is consumed during the reaction with $H_2SO_4$
10%
C
$H_2SO_4$ doesnot react with $KMnO_4$ or the reducing agent used
68%
D
$H_2SO_4$ can turn colourless $KMnO_4$ to pink at the end point
10%
Solution:
See properties of $KMnO_4$